Question

(x-1)(x^2+8x+16)=6(x+4)

Answer 1

$(x-1)(x^2+8x+16)=6(x+4) \ (x-1)(x^2+2*4*x+4^2)=6(x+4) \ (x-1)(x+4)^2=6(x+4) \ x = -4; \ (x-1)(x+4)=6 \ x^2+4x-x-4-6=0 \ x^2+3x-10 = 0 \ D=3^2+10*4= 49 \ x_{1,2} = frac{-3б7}{2} \ x_1 = -5; x_2 = 2 ; x_3 = -4$