Question

x^2+5x/x^2-10x+25 : (5/x+5 + x^2+25/x^2-25 - 5/5-x)

Answer 1

1) (x²+5x)/(x²-10x+25) =
(x(x+5) /(x -5)²

2) 5/5-x = -5/x-5
x²-25=(x-5)(x+5)это общий знаменатель

(5(x-5)+x²+25 +5(x+5)) /(x-5)(x+5) =(5x-25+x²+25 + 5x+25) /(x -5)(x +5) =
(x²+ 10x+25) /(x-5)(x+5) =
(x +5)²) /(x -5)(x +5) =
=(x +5) /(x -5)
при делении дробь переворачиваем и будет умножение (x+5)/(x-5)= (x-5)/(x+5)

x(x+5) *(x-5) / (x-5)² *(x+5) = x /(x -5)