Question

(2у-1)(4у²+2у+1)-у(у-1)(у+1)

Answer 1

(2y – 1)(4y² + 2y + 1) – y(y – 1)(y + 1) = 8y³ + 4y² + 2y – 4y² – 2y – 1 – y(y² – 1²) = 8y³ – 1 – y³ + y = 7y³ + y – 1