Question

2x^2-4x+3x^2-4x^2+3=0

Answer 1

x^2 - 4x + 3 = 0 
D = 16 - 12 = 4 = 2²
x₁ = ( 4 + 2)/2 = 6/2 = 3;
x₂ = ( 4 - 2)/2 = 2/2 = 1 ; 

Answer 2

x^2-4x+3=0
a=1, b=-4, c=3
D=b^2-4*a*c=16-12=4
x1=(4+2)/2=3
x2=(4-2)/2=1