Question

Помогите пожалуйста 2 и 4 прошу........сфоткайте пожалуйста

Answer 1

$2); ; |2x-1|+|x-3| leq 4\\Znaki; (2x-1):; ; ---(frac{1}{2})++++++++\\Znaki; (x-3):; ; ; --------(3)++++\\a); x leq frac{1}{2}; to ; ; |2x-1|=-(2x-1); ,; |x-3|=-(x-3)\\-2x+1-x+3 leq 4; ,; ; ; -3x leq 0; ,; ; x geq 0; ; to \\xin [, 0,frac{1}{2}, ]\\b); frac{1}{2} textless x leq 3; ,; |2x-1|=2x-1; ,; ; |x-3|=-(x-3)\\2x-1-x+3 leq 4; ,; ; ; x leq 2; ; to \\xin (frac{1}{2},2, ]\\c); x textgreater 3; ,; ; |2x-1|=2x-1; ,; |x-3|=x-3$

 $2x-1+x-3 leq 4; ,$  $3x leq 8,; ; x leq frac{8}{3}; ,; ; x leq 2frac{2}{3}; ,; 2notin (3,+infty ); ; to$   

$xin varnothing \\Otvet:; ; xin [, 0,frac{1}{2}, ]cup(frac{1}{2},, 2]; ; to ; ; xin [, 0,2, ], .$

$2); ; sqrt{x+27} textgreater x-3; ; to\\ left { {{x-3 geq 0} atop {x+27 textgreater (x-3)^2}} right. ; ; ; ili; ; ; left { {{x-3 leq 0} atop {x+27 geq 0}} right. \\ left { {{x geq 3} atop {x^2-7x-18 textless 0}} right. ; ; ; ili; ; ; ; left { {{x leq 3} atop {x geq -27}} right. \\ left { {{x geq 3} atop {(x+2)(x-9) textless 0}} right. ; ; ; ili; ; ; ; -27 leq x leq 3\\ left { {{xin [, 3,+infty )} atop {xin (-2,9)}} right. ; ; ; ili; ; ; xin [-27,3, ]$

$xin [, 3,9); ; ; ; ; ili; ; ; ; ; xin [-27,3, ]\\xin [-27,9)$