Question

Решите пожалуйста
1)16х^2>169
2)√44*11*40
3)(8х-5)(-5х-8)=0

Answer 1

$16x^2 textgreater 169 \ x^2 textgreater frac{169}{16} \ x textgreater frac{13}{4},x textless - frac{13}{4}$
x∈(-∞;-13/4)∨(13/4;+∞)

$sqrt{44*11*40}= sqrt{4*11*11*4*10}=4*11 sqrt{10}=44 sqrt{10} \ \ (8x-5)(-5x-8)=0 \ 8x-5=0,x_1= frac{5}{8} \ -5x-8=0,x_2=- frac{8}{5}=-1.6$