Question

2log^2x-7log3 x+3=0 помогите

Answer 1

ОДЗx>0
log(3)x=a
2a²-7a+3=0
D=49-24=25
a1=(7-5)/4=1/2⇒log(3)x=1/2⇒x=√3
a2=(7+5)/4=3⇒log(3)x=3⇒x=27