Question

Определить массовую долю каждого элемента и вычислить молекулярную массу следующих веществ:CH4, C2H2, C2H6, C2H4, C6H6

Answer 1

СН4

W(C) = Ar(C) * n / Mr(CH4) *100% = 12 * 1 / 16  *100% = 75%

W(H) = Ar(H) * n / Mr(CH4) *100% = 1 * 4 / 16 *100% = 25 %

С2Н2

W(C) = Ar(C) * n / Mr(C2H2) *100% = 12*2 / 26 *100% = 92%

W(H) = Ar(H) * n / Mr(C2H2) *100% = 1 *2 / 26 * 100% = 8%

С2Н6

W(C) = Ar(C) * n / Mr(C2H6) *100% = 12 *2 / 30 *100% = 80%

W(H) = Ar(H) * n / Mr(C2H6) *100% = 1 *6 | 30 * 100% = 20%

C2H4

W(C) = Ar(C) * n | Mr(C2H4) * 100% = 12 *2 / 28 *100% = 85,7%

W(H) = Ar(H) *n / Mr(C2H4) * 100% = 1*4 / 28 *100% = 14,3%

С6Н6

W(C) = Ar(C) * n / Mr(C6H6) *100% = 12 *6 / 78 *100% = 92,3%

W(H) = Ar(H) * n / Mr(C6H6) *100% = 1 * 6 / 78 *100% = 7,7%