Question

Найдите корни уравнения 4x^2+6x-2=(x-1)^2

Answer 1

4x^2+6x-2=(x-1)^2

4x^2+6x-2=х^2-2x+1

4x^2+6x-2-х^2+2x-1=0

3x^2+8x-3=0

D=64+36=100

x1=(-8+10)/6     x1=1/3

x2=(-8-10)/6      x2=-3

Answer 2

4x^2+6x-2=(x-1)^2

4x^2+6x-2 -x^2 + 2х - 1 = 0

3x^2+8x-3 = 0

d = 8*8 - 4*3* (-3) = 64+36 = 100

х1 = (-8-10)/6 = -18/6 = -3

х2 = (-8+10)/6 = 2/6 = 1/3