Question

ПРЕДСТАВЬТЕ В ВИДЕ МНОГОЧЛЕНА

Answer 1

$(-0,6 +2c)^2 =(2c-0,6)^2 = 4c^2 - 2,4c+0,36 \ (-0,3+4p)^2 = (4p-0,3)^2 = 16p^2 -2,4p+0,09 \ (-1,2+5m)^2 = (5m-1,2)^2 = 25m^2 -12m+1,44 \ (-3a+0,5)^2 =(0,5 -3a)^2 =0,25-3a+9a^2 \ (-8u+0,5)^2 = (0,5-8u)^2 = 0,25 -8u+64u^2 \ (-7x+1,1)^2=(1,1-7x)^2 = 1,21-15,4x+49x^2 \ (-8-0,3a)^2 = (0,3a+8)^2 = 0,09a^2 +4,8a+64 \ (-5-1,5c)^2 =(1,5c+5)^2 = 2,25c^2 +15c+25 \ (-9-1,2y)^2 = (1,2y+9)^2 = 1,44y^2 +21,6y+81 \ (-2x-0,7)^2 =(2x+0,7)^2 = 4x^2 +2,8x+0,49 \ (-6n-0,3)^2 = (6n+0,3)^2 = 36n^2 +3,6n+0,09$

$(-8t-2,5)^2 = (8t+2,5)^2 = 64t^2 +40t+6,25$