Question

решить интегралы

1)∫_(-1)^2▒〖(5x+2)dx〗

2)∫_(-1)^2▒〖(4x+1)dx〗

Answer 1

2) ∫(4x+1)dx [-1;2] = 2x^2+x [-1;2] = F(2)-F(-1) = 8 + 2 - (2-1) = 10 - 1 = 9
1) ∫(5x+2)dx [-1;2] = 5x^2/2 + 2x [-1;2] = F(2)-F(-1) = 20/2 + 4 - (5/2 - 2 ) = 14 - 2.5 + 2 = 13.5