Question

Приведи многочлен стандартного вида!
1)(2a-5)^2+5(4a-5)
2)a(a-4)+(a-2)(a+4)
3)(b+5c)^2-(5c-b)^2

Answer 1

1)(2a-5)²+5(4a-5)=4a²-20a+25+20a-25=4a²
2)a(a-4)+(a-2)(a+4)=a²-4a+a²+2a-8=2a²-2a-8
3)(b+5c)²-(5c-b)²=(b+5c+5c-b)(b+5c-5c+b)=10c.2b=20bc