Question

1) (x³+8):(x²-2x+4)
2)(1+x)(1-x)(1+x²)
3)5x²-3(x+1)(x-1)

Answer 1

1) (x³+8):(x²-2x+4)=$frac{(x+2)(x^2-2x+4)}{x^2-2x+4} =x+2$
2)(1+x)(1-x)(1+x²)=(1-x²)*(1+x²)=1-x⁴
3)5x²-3(x+1)(x-1)=5x²-3(x+1)(x-1)= 5x²-3(x²-1) = 5x²-3x²-3 = 2x² - 3.