Question

найдите решение системы 6(х+у) 8+2х-3у 5(у-х) 5+3х+2у

Answer 1

6х+6у х 8+2х-3у х5у-5х х 5+3х
2у=6х+10у х 40

Answer 2

$left{{{6(x+y)=8+2x-3y}atop{5(y-x)=5+3x+2y}}right.left{{{6x+6y=8+2x-3y}atop{5y-5x=5+3x+2y}}right.left{{{6x+6y-2x+3y=8}atop{5y-5x-3x-2y=5}}right.\left{{{4x+9y=8}atop{3y-8x=5}}right.left{{{4x+9y=8/2}atop{3y-8x=5}}right.left{{{8x+18y=16}atop{3y-8x=5}}right.$
$8x+18y+3y-8x=5+16\21y=21;y=1\----\6(x+y)=8+2x-3y\6(x+1)=8+2x-3\6x+6=5+2x\6x-2x=5-6\4x=-1;x=-frac{1}{4}=-0,25$