Question

sin п(2x-7)4=корень из22

Answer 1

π(2x-7)/4=π/4+2πn U π(2x-7)/4=3π/4+2πk
2x-7=1+8n⇒2x=8+8n⇒x=4+4n,n∈z U 2x-7=3+8k⇒2x=10+8k⇒x=5+4k,k∈z