Question

Помогите!!!! Срочно
(3sinx−3)(tgx−1/корень3) = 0

Answer 1

[3sinx-3=0⇒3sinx=3⇒sinx=1⇒x=π/2+2πn,n∈z
[tgx-1/√3=0⇒tgx=1/√3⇒x=π/6+πk,k∈z