Question

Решить уравнения

3 tg (x- π/6) = √3
2 sin( 4x- π)= √2

Answer 1

1)3tg(x-π/6)=√3
     tg(x-π/6)=√3/3
      x-π/6=π/6+k.π
      x=π/6+π/6+k.π
      x=π/3+k.π , k∈Z
2)2.sin(4x-π)=√2
      sin(4x-π)=√2/2
    a)4x-π=π/4+2k.π
       4x=π+π/4 +2k.π=5/4.π+2k.π
        x=5π/16+k.π/2
    b)4x-π=3π/4+2k.π
        4x=π+3π/4 +2k.π=7π/4+2k.π
         x=7π/16+k.π/2
k∈Z