Question

sin (4x-п/3)= корень из 3/2

Answer 1

4x-π/3=((-1)^n)*arcsin√3/2+πn=((-1)^n)π/3+πn, n∈Z
4x=((-1)^n)π/3+π/3+πn
x=((-1)^n)π/12+π/12+πn/4