Question

Решите неравенство. Срочно
$frac{2x-3}{x+1} textgreater 1$

Answer 1

$frac{2x-3}{x+1} textgreater 1, frac{2x-3}{x+1}-1 textgreater 0$
$frac{2x-3-(x+1)}{x+1} textgreater 0 , frac{x-4}{x+1} textgreater 0$
метод интервалов:
$left { {{x-4=0} atop {x+1 neq 0}} right. , left { {{x=4} atop {x neq -1}} right.$
      +                     -               +
-------------(-1)-----------(4)-------------->x

x∈(-∞;-1)∪(4;∞)