Question

$x^-4 {y} =-1, 3 x_- {y} =8$

Решите систему уравнений

Answer 1

x-4y=-1
3x-y=8

x=4y-1
3(4y-1)-y=8

12y-3-y=8
11y=11
y=1

x=4-1
x=3