Question

(3x-1)^2-8(x+1)^2=(x+2)(x-2)

Answer 1

(3х-1)² - 8(х+1)² = (х+2)(х-2)
9х²-6х+1 - 8(х²+2х+1) = х²-4
9х²-6х+1-8х²-16х-8 = х²-4
х²-22х-7 = х²-4
х²-х²-22х = -4+7
-22х = 3
х = 3 : (-22)
х = $-frac{3}{22}$
Ответ: $- frac{3}{22}$.