Question

Решите систе
му уравнений {x+y=-2 {x^2-2xy+y^2=16

Answer 1

x+y=-2   y=-2-x
x^2-2xy+y^2=16

x^2-2x(-2-x)+(-2-x)^2=16
x^2+4x+2x^2+4+4x+x^2=16
4x^2+8x-12=0   |:4
x^2+2x-3=0
x1*x2=-3   x1=-3
x1+x2=-2  x2=1
-3+y=-2
y1=1
1+y=-2
y2=-3
Ответ:(-3;1),(1;-3)