Question

Помогите пожалуйста) 1)(sin23°cos22°+cos23°sin22°)(cos24°cos21°-sin24°sin21°)
2)(sin(a+3ß)+sin(a-3ß))/(sin(a+3ß)-sin(a-3ß))*ctga
3)(sin38°+sin22°)/cos8°

Answer 1

1
sin(23+22)*cos(24+21)=sin45*cos45=0,5sin90=0,5*1=0,5
2
2sinacos3b/2sin3bcosa *ctga=tga*ctg3b *ctga=ctg3b
3
2sin30cos8/cos8=2sin30=2*1/2=1