Question

(6-с)^2-c(c+3)
при с=-1/15

Answer 1

$c=- frac{1}{15}$
$(6-c)^2-c(c+3)=36-12c+c^2-c^2-3c=36-15c$
$36-15c=36-15*(- frac{1}{15} )=36+1=37$