Question

(2х-5)во 2 степени+(х-3)(х-5)=40

Answer 1

(2х-5)²+(х-3)(х-5)=40
4х²-20х+25+(х²-5х-3х+15)=40
4х²-20х+25+х²-5х-3х+15-40=0
5х²-28х=0
х(5х-28)=0
х=0
5х-28=0
5х=28
х=28/5