Question

решите уравнение $x^{2} +y^{2} - 8x +12y +52=0$

Answer 1

x²+y²-8x+12y+52=0
x²-8x+16+y²+12y+36=0
(x-4)²+(y+6)²=0
(x-4)²=0 ∧ (y+6)²=0
a)(x-4)²=0, x-4=0, x=4
b)(y+6)²=0, y+6=0,y=-6
/x,y/=/4, -6/
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