Question

(2x^2-128)/(x^3-16x^2+64x)

Answer 1

$frac{2x^2-128}{x^3-16x^2+64x} = frac{2(x^2-64)(x+8)}{x(x^2-16x+64)} = frac{2(x-8)(x+8)}{x(x-8)^2} = frac{2(x+8)}{x(x-8)}$