Question

СРОЧНо умоляю!1пример!
(8номнр)

Answer 1

f(x) = Cos(2x + π/3)  + 2х
f'(x) = -2Sin(2x + π/3) + 2
-2Sin(2x + π/3) + 2 = 0
Sin(2x + π/3) = 1
2x + π/3 = π/2 + 2πk, k ∈Z
2x = π/2 + 2πk - π/3, k ∈Z
2x = π/6 + 2πk, k ∈Z
x = π/12 + πk, k ∈Z

Answer 2

Вы просто супер! Большое спасибо !)

Answer 3

рад, если помог...

Answer 4

Очень помог)

Answer 5

F (x) равен = Cos (2x+ π / 3) и + 2x F (x) равен = -2 sin (2x + π/3) и + 2 - 2 Sin (2x + π/3) + 2 равно = 0 Sin (2x + π/3) равно = 1 2x + 3/π равно = π/2 + 2πk k ∈Z 2x равно = π/2 + 2πk - π/3 k ∈Z 2x равен = π/6 + 2πk k ∈Z x равен = π/12 + πk k ∈Z