Question

помогите решить задачку срочно {x-у=2 {у²-2ху=3

Answer 1

According to the first equation，x=y+2,then we put it into the second equation,we get the new equation：
у²-2（y+2）y =3
у²-2（у²+2y）=3
у²-2у²-4y=3
-у²-4y=3
у²+4y+3=0
（y+3）*（y+1）=0
y=-3，x=-1 or
y=-1，x=1