Question

решите 4 пожалуйста
(если можно подробно)

Answer 1

$frac{2 sqrt{2}-5 }{ sqrt{2} -1} + frac{3sqrt{6}-sqrt{300}}{sqrt{3}} = frac{2sqrt{2}-5}{sqrt{2}-1} + frac{3sqrt{3}*sqrt{2}-sqrt{3}*sqrt{100}}{sqrt{3}} = \ \ = frac{2sqrt{2}-5}{sqrt{2}-1} + frac{sqrt{3}*(3sqrt{2}-10)}{sqrt{3}} = frac{2sqrt{2}-5}{sqrt{2}-1} +3sqrt{2}-10= \ \ =frac{2sqrt{2}-5+(3sqrt{2}-10)*(sqrt{2}-1)}{sqrt{2}-1} = frac{2sqrt{2}-5+6-3sqrt{2}-10sqrt{2}+10}{sqrt{2}-1} = \ = frac{-11sqrt{2}+11}{sqrt{2}-1}= frac{-11(sqrt{2}-1)}{sqrt{2}-1} =- 11$

Ответ: 11