Question

(x^2-6x)^5=(2x-7)^5 помогите)

Answer 1

(x²-6x)^5=(2x-7)^5
(x²-6x-2x+7)^5=0
(x²-8x+7)^5=0
D=64-28=36
√D=6
x₁=(8+6)/2=7
x₂=(8-6)/2=1
Ответ:x₁=7,x₂=1