Question

Помогите пожалуйста <3

Answer 1

1)2x^2 - 5x + 3 <= 0
D = 25 - 24 = 1
x = (5 +- 1) / 4, x1 = 1, x2 = 3/2
(x - 1)(x - 3/2) <= 0
x ∈ [1; 3/2]

2) (x - 1)(x - 4) / (x - 3) / (x + 3) < 0
x ∈ (-3; 1) ∪ (3; 4)

3)(x - 3) ^ 2 * (x - 4) * (x + 4) <= 0
x ∈ (-∞; -4]∪{3}∪[4; ∞)

4)(x + 1) ^ 2 * x / (3 - x) >= 0
x ∈ {-1}∪[0; 3]

5) (x - 7)(x + 7) / (x - 1) / (x - 8) <= 0
x ∈ [-7; 1] ∪ [7; 8]