Question

ПРЕДЕЛ ФУНКЦИИ ! Помогите!!!!!!!!!!!!!

Answer 1

$lim_{x to -1} frac{(x+3)*(x-2)}{x+2} = frac{(-1+3)*(-1-2)}{-1+2} =-6$
$lim_{x to [tex]= lim_{x to 3} ( frac{6-1*(x+3)}{ x^{2} -9} )= lim_{x to 3} frac{-(x-3)}{(x+3)*(x-3)} = lim_{x to 3} frac{-1}{x+3} =- frac{1}{6}$