Question

1) log7(3x-1)=2
2)log2(2x-7)=log2(x+5)

1) (12)^x=32
2) корень 32=4^x2

Answer 1

1) 3х-1=49
3х=50
Х=50/3

2)2х-7=х+5
Х=12

1) х=log[1/2](32)
X=-5

2^(5/2)=2^x
X=5/2