Question

√32(2cos^2 (3Π/8) -1) помогите решить

Answer 1

√128сos²3π/8-√32=4√2*(2cos²3π/8-1)=4√2^cos3π/4=
=4√2*cos(π-π/4)=4√2*(-cosπ/4)=4√2*(-1/√2)=-4