Question

Найти производную функции у=(2х+1)^1/2 ÷ tgX

Answer 1

y=(√2x+1)/tgx
y⁾=((2tgx/2(√2x+1)-(√2x+1)/cos²x)/tg²x=
=(sinxcosx-2x-1)/tg²x*cos²x*√2x+1=(sinx*cosx-2x-1)/sin²x*√2x+1