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cos(π/2+x) = 1
π/2 + x = 2πk ; k∈Z
x= 2πk - π/2 = (4k-1)·π/2 ; k∈Z
log(5) (5-x) - log(5) 3 = 0
log(5) [(5-x)/3] = 0
(5-x)/3 = 1
5-x = 3
x=2
cosx = 1/√2 = √2/2
x = +/-π/4 + 2πk ; k∈Z
π/2 + x = 2πk ; k∈Z
x= 2πk - π/2 = (4k-1)·π/2 ; k∈Z
log(5) (5-x) - log(5) 3 = 0
log(5) [(5-x)/3] = 0
(5-x)/3 = 1
5-x = 3
x=2
cosx = 1/√2 = √2/2
x = +/-π/4 + 2πk ; k∈Z
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