Question

2sin^2x-sinxcosx=0
решите плииз

Answer 1

2sin^2x-sinxcosx=0
sinx(2sinx-cosx)=0
sinx=0
x=пk
2sinx-cosx=0
2tgx-1=0
2tgx=1
tgx=1/2
x=arctg(1/2)+пn