Question

log12 1440- log12 10+ 3log9 16

Answer 1

Решение тут...............................

Answer 2

㏒12(1440)-㏒12()10+㏒9(16)=㏒12(144010)+㏒9(16³)=
㏒12(144)+㏒9(4096)=2+㏒9(4096)=㏒9(81)+㏒9(4096)=
㏒9(81·4096)=㏒9(331776)