Question

помогите алгебра(логарифмы)!!!!!(4)

Answer 1

a
log(5)150-log(5)3+log(5)1/2-log(5)1=log(5)(150/6)-0=log(5)25=2
b
10^(2-3lg5)=10²:10^3lg5=100:10^log(5)125=100/125=0,8

Answer 2

$log_5150 - log_53 + log_5 frac{1}{2} - log_51 = log_5 frac{150}{3*2}=log_525 = log_55^2 = 2$