Question

cos2х*sin4х=cosx*sin5x решить уравнение

Answer 1

1/2sin2x+1/2sin6x-1/2sin4x-1/2sin6x=0
1/2*(sin2x-sin4x)=0
1/2*(-2sinxcos3x)=0
sinx=0
x=πn,n∈z
cos3x=0
3x=π/2+πk
x=π/6+πk/3,k∈z