Question

Sin^2(-30градусов)-2ctg(-30градусов)-1/
/2-tg45градусов+4cos^2(-60градусов)

Answer 1

[(-1/2)²-2*(-√3)-1]/[2-1+4*(1/2)²]=(0,25+2√3-1)/(1+1)=(2√3-0,75)/2

Answer 2

$frac{sin^2(-30)-2ctg(-30)-1}{2-tg45+4cos^2(-60)} = frac{(frac{1}{2})^2-2cdot (-sqrt3)-1}{2-1+4cdot (frac{1}{2})^2} =\\= frac{frac{1}{4}+2sqrt3-1}{2-1+1}= frac{2sqrt3-frac{3}{4}}{2} = frac{8sqrt3-3}{4cdot 2} = frac{8sqrt3-3}{8} =sqrt3-frac{3}{8}$