Question

Первообразная и интеграл

Answer 1

f
s(t)=6t²+4t+C
s(1)=6+4+C=12
C=2
s(t)=6t²+4t+2
b
s(t)=4t²-4t+C
s(2)=16-8+C=4
C=-4
s(t)=4t²-4t-4