Question

Sin 5x+¶/5=-√3/2 решить уравнение

Answer 1

$sin(5x+frac{pi}{5})=-frac{sqrt3}{2}\\5x+frac{pi}{5}=(-1)^{n}arcsin(-frac{sqrt3}{2})+pi n=(-1)^{n+1}arcsinfrac{sqrt3}{2}+pi n\\5x+frac{pi}{5}=(-1)^{n+1}frac{pi}{3}+pi n,; nin Z\\5x=-frac{pi}{5}+(-1)^{n+1}frac{pi}{3}+pi n,; nin Z\\x=-frac{pi}{25}+(-1)^{n+1}frac{pi}{15}+frac{pi n}{5}; ,; nin Z$