Question

решить уравнение х+1=корень из 1-х

Answer 1

$x+1=sqrt{1-x}; ; ODZ:; x+1 geq 0; , xgeq -1\\\\(x+1)^2=1-x\\x^2+2x+1=1-x\\x^2+3x=0\\x(x+3)=0\\x_1=0; ,; x_2=-3notin ODZ\\Otvet:; x=0.$

Answer 2

$left { {{x+1 = sqrt{1-x} } atop {x+1 textgreater 0}} right. left { {{x^{2} +2x +1 = 1-x atop {x textgreater -1}} right. left { {{x^{2} +3x= 0 atop {x textgreater -1}} right. left { {{x(x+3)= 0 atop {x textgreater -1}} right. left { {{ left { {{x=0} atop {x=-3 }} right. atop {x textgreater -1}} right. x = 0$

Ответ: 0

Answer 3

Я имел в виду >=, а не > ;)