Question

найти производную функции s=e2t*cos2t

Answer 1

$s'=(e^{2t}*cos2t)'=(e^{2t})'*cos2t+(cos2t)'*e^{2t}= \ \ =2e^{2t}cos2t-2e^{2t}sin2t=2e^{2t}(cos2t-sin2t)$