Question

log3(x-1)+log3(x+3)=1

Answer 1

{x-1>0⇒x>1
{x+3>0⇒x>-3
x∈(1;∞)
log(3)[(x-1)(x+3)]=1⇒x²+2x-3=3⇒x²+2x-6=0
D=4+24=28
x1=(-2-2√7)/2=-1-√7не удов усл
x2=-1+√7

Answer 2

Log3(x-1)(x+1)=1
(x-1)(x+2)=3^1
x^2+x*3-1x-3=0
x^2+2x-6=0

Дальше сам/сама