Question

решите первый номер пожалуйста

Answer 1

sin(360+60)+cos(360-60)-tg(180+30)=sin60+cos60-tg30=
=√3/2+1/2-√3/3
sin(2π-π/4)-cos(2π-π/3)=-sinπ/4-cosπ/3=√2/2-1/2

Answer 2

$sin420+cos300-tg210=\\=sin(360+60)+cos(360-60)-tg(180+30)=\\=sin60+cos60+tg30=frac{sqrt3}{2}+frac{1}{2}+frac{sqrt3}{3}= frac{3sqrt3+3+2sqrt3}{6} =frac{5sqrt3+3}{6}\\2)quad sinfrac{7}{4}pi -cosfrac{5}{3}pi =sin(2pi -frac{pi}{4})-cos(2pi -frac{pi}{3})=\\=-sinfrac{pi}{4}-cosfrac{pi}{3}= -frac{sqrt2}{2}-frac{1}{2}=-frac{sqrt2+1}{2}$