Question

log4(x+1)-2=log4 (3-x)

Answer 1

{x+1>0⇒x>-1
{3-x>0⇒x<3
x∈(1;3)
log(4)(x+1)=log(4)[(3-x)*16]
x+1=48-16x
x+16x=48-1
17x=47
x=2 13/17