Question

Помогите... в универ надо

Answer 1

1
$(3a ^{1/6} -2b ^{1/6} )(a ^{1/6} -b ^{1/6} )(a ^{1/6} +b ^{1/6} )-3/(a ^{1/6} +b ^{1/6} )=$$(3a ^{1/6} -2b ^{1/6} -3a ^{1/6} +3b ^{1/6} )(a ^{1/3} -b ^{1/3} )=b ^{1/6} /(a ^{1/3} -b ^{1/3} )$
2
$b ^{1/6} /(a ^{1/3} -b ^{1/3} )*b ^{5/6} /(a ^{2/3} +(ab) ^{1/3} +b ^{2/3} )=b/(a-b)$
a=3,9  b=2,6
2,6/(3,9-2,6)=2,6/1,3=2

Answer 2

Спасибо большое